The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface, having work function 5.01 eV, when ultraviolet light of 200 nm falls on it, must be
- 2.4 V
- -1.2 V
- -2.4 V
- 1.2 V
Answer
(2) -1.2 V
Solution
Energy of a photon, E = hc = 1240 eV nm200 nm = 6.2 eV
Kmax = E - 0 = 6.2 - 5.01 1.2 eV
eV0 = 1.2 eV V0 = 1.2 V
To stop the photoelectrons, the collector must be made negative with respect to the emitter.
Potential to be applied = -1.2 V
Answer: (2)