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Coordination Compounds · Question 54

JEE Main 2025 (Online) 29th January Morning ShiftMCQMedium📈 Topic in 55% papers+4−1
1

The correct increasing order of stability of the complexes based on 0 value is : I. [Mn(CN)6]3- II. [Co(CN)6]4- III. [Fe(CN)6]4- IV. [Fe(CN)6]3-

  1. I < II < IV < III
  2. IV < III < II < I
  3. III < II < IV < I
  4. II < III < I < IV

Answer

(1) I < II < IV < III

Solution

CN- is a strong-field ligand all four complexes are low spin.

CFSE = (-0.4 x + 0.6 y) 0 for t2gx egy

I. Mn3+, 3d4: t2g4 eg0 CFSE = -1.6 0

II. Co2+, 3d7: t2g6 eg1 CFSE = -2.4 + 0.6 = -1.8 0

III. Fe2+, 3d6: t2g6 eg0 CFSE = -2.4 0

IV. Fe3+, 3d5: t2g5 eg0 CFSE = -2.0 0

Greater the magnitude of CFSE, greater the stability.

Stability: I < II < IV < III

Answer: (1)

JEE Main 2025 (Online) 29th January Morning Shift

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2

Match List - I with List - II. Choose the correct answer from the options given below :

  1. (A)-(III), (B)-(I), (C)-(I), (D)-(IV)
  2. (A)-(III), (B)-(II), (C)-(III), (D)-(IV)
  3. (A)-(IV), (B)-(II), (C)-(I), (D)-(III)
  4. (A)-(IV), (B)-(I), (C)-(II), (D)-(III)
JEE Main 2025 (Online) 29th January Morning Shift
3

Match List - I with List - II. Choose the correct answer from the options given below:

  1. (A)-(I), (B)-(II), (C)-(III), (D)-(IV)
  2. (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
  3. (A)-(I), (B)-(IV), (C)-(III), (D)-(II)
  4. (A)-(III), (B)-(II), (C)-(I), (D)-(IV)
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