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Units and Measurements

JEE Main 2024 (Online) 8th April Evening ShiftMCQEasy📈 Topic in 34% papers+4−1
Ques. 1JEE Main 2024, 8 April (Evening Shift)

There are 100 divisions on the circular scale of a screw gauge of pitch 1 mm. With no measuring quantity in between the jaws, the zero of the circular scale lies 5 divisions below the reference line. The diameter of a wire is then measured using this screw gauge. It is found that 4 linear scale divisions are clearly visible while 60 divisions on circular scale coincide with the reference line. The diameter of the wire is :

  1. 4.65 mm
  2. 4.60 mm
  3. 4.55 mm
  4. 3.35 mm

Answer

(3) 4.55 mm

Solution

Least count = pitch ÷ circular divisions = 1 mm100 = 0.01 mm

zero of circular scale below the reference line ⇒ positive zero error = +5 0.01 = +0.05 mm

Observed reading = 4 1 + 60 0.01 = 4.60 mm

Hence diameter = observed reading − zero error = 4.60 - 0.05 = 4.55 mm

Answer: (3)

Keep practising — Units and Measurements

Ques. 2JEE Main 2024, 8 April (Evening Shift)

Least count of a vernier caliper is 120 N cm. The value of one division on the main scale is 1 mm. Then the number of divisions of main scale that coincide with N divisions of vernier scale is :

  1. ( 2N - 12N )
  2. ( 2N - 120N )
  3. (2N - 1)
  4. ( 2N - 12 )
Ques. 3JEE Main 2024, 6 April (Morning Shift)

To find the spring constant (k) of a spring experimentally, a student commits 2\% positive error in the measurement of time and 1\% negative error in measurement of mass. The percentage error in determining value of k is :

  1. 5\%
  2. 3\%
  3. 1\%
  4. 4\%
Ques. 4JEE Main 2024, 6 April (Morning Shift)

While measuring diameter of wire using screw gauge the following readings were noted. Main scale reading is 1 mm and circular scale reading is equal to 42 divisions. Pitch of screw gauge is 1 mm and it has 100 divisions on circular scale. The diameter of the wire is x50 mm. The value of x is :

  1. 42
  2. 71
  3. 21
  4. 142
Ques. 5JEE Main 2024, 6 April (Evening Shift)

Given below are two statements: In the light of the above statements, choose the most appropriate answer from the options given below.

  1. Statement (I) is incorrect but statement (II) is correct
  2. Both statement (I) and statement (II) are incorrect
  3. Both statement (I) and statement (II) are correct
  4. Statement (I) is correct but statement (II) is incorrect
Ques. 6JEE Main 2024, 6 April (Evening Shift)

In a vernier calliper, when both jaws touch each other, zero of the vernier scale shifts towards left and its 4th division coincides exactly with a certain division on main scale. If 50 vernier scale divisions equal to 49 main scale divisions and zero error in the instrument is 0.04 mm then how many main scale divisions are there in 1 cm ?

  1. 5
  2. 40
  3. 10
  4. 20
Ques. 7JEE Main 2024, 5 April (Morning Shift)

If G be the gravitational constant and u be the energy density then which of the following quantity have the dimensions as that of the uG :

  1. Gravitational potential
  2. pressure gradient per unit mass
  3. Energy per unit mass
  4. Force per unit mass
Ques. 8JEE Main 2024, 5 April (Morning Shift)

Time periods of oscillation of the same simple pendulum measured using four different measuring clocks were recorded as 4.62 s, 4.632 s, 4.6 s and 4.64 s. The arithmetic mean of these readings in correct significant figure is :

  1. 5 s
  2. 4.6 s
  3. 4.62 s
  4. 4.623 s
Ques. 9JEE Main 2024, 5 April (Evening Shift)

What is the dimensional formula of ab-1 in the equation (P + aV2 )(V - b) = RT, where letters have their usual meaning.

  1. [M6 L7 T4]
  2. [ M-1 L5 T3]
  3. [ M0 L3 T-2]
  4. [ M L2 T-2]
Ques. 10JEE Main 2024, 5 April (Evening Shift)

A vernier callipers has 20 divisions on the vernier scale, which coincides with 19th division on the main scale. The least count of the instrument is 0.1 mm. One main scale division is equal to mm.

  1. 5
  2. 2
  3. 1
  4. 0.5
Ques. 11JEE Main 2024, 4 April (Morning Shift)

The equation of stationary wave is : y=2a ( 2 ) ( 2 x ). Which of the following is NOT correct :

  1. The dimensions of nt is [L]
  2. The dimensions of n is [ LT-1]
  3. The dimensions of x is [L]
  4. The dimensions of n/ is [T]

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