Time periods of oscillation of the same simple pendulum measured using four different measuring clocks were recorded as 4.62 s, 4.632 s, 4.6 s and 4.64 s. The arithmetic mean of these readings in correct significant figure is :
- 5 s
- 4.6 s
- 4.62 s
- 4.623 s
Answer
(2) 4.6 s
Solution
T = 4.62 + 4.632 + 4.6 + 4.644 = 18.4924 = 4.623 s
the least precise reading, 4.6 s, has only one decimal place, the mean is rounded to one decimal place.
T = 4.6 s
Answer: (2)