Least count of a vernier caliper is 120 N cm. The value of one division on the main scale is 1 mm. Then the number of divisions of main scale that coincide with N divisions of vernier scale is :
- ( 2N - 12N )
- ( 2N - 120N )
- (2N - 1)
- ( 2N - 12 )
Answer
(4) ( 2N - 12 )
Solution
LC = 120N cm = 12N mm and 1 MSD = 1 mm
Let x MSD coincide with N VSD ⇒ 1 VSD = xN mm
LC = 1 MSD − 1 VSD
12N = 1 - xN
x = N - 12 = 2N - 12
Answer: (4)