The potential energy function (in J) of a particle in a region of space is given as U= (2x2+3y3+2z ). Here x, y and z are in meter. The magnitude of x-component of force (in N) acting on the particle at point P(1,2,3) m is :
- 4
- 2
- 8
- 6
Answer
(1) 4
Solution
Conservative force: Fx=- U x
Fx=- x (2x2+3y3+2z )=-4x
At P(1,2,3): Fx=-4(1)=-4 N
|Fx|=4 N
Answer: (1)