1
At 300 K, an ideal dilute solution of a macromolecule exerts osmotic pressure that is expressed in terms of the height (h) of the solution (density = 1.00 g cm-3) where h is equal to 2.00 cm. If the concentration of the dilute solution of the macromolecule is 2.00 g dm-3, the molar mass of the macromolecule is calculated to be X 104 g mol-1. The value of X is . Use: Universal gas constant (R) = 8.3 J K-1 mol-1 and acceleration due to gravity (g) = 10 m s-2
Answer
2.4 to 2.55
Solution
= h g = wM RTV (SI units)
= 0.02 m 1000 kg m-3 10 m s-2 = 200 Pa
Concentration = 2.00 g dm-3 = 2000 g m-3
M = 2000 8.3 300200 = 24900 g mol-1 = 2.49 104 g mol-1
Answer: 2.49
JEE Advanced 2025 Paper 2