Two nuclei have their mass numbers in the ratio of 1 : 3. The ratio of their nuclear densities would be
- (3)1/3 : 1
- 1 : 1
- 1 : 3
- 3 : 1
Answer
(2) 1 : 1
Solution
Nuclear radius: R = R0A1/3
⇒ Volume V = 43 R03A, i.e., V A
Mass M A
∴ Density = MV is independent of A.
⇒ 1 : 2 = 1 : 1
Answer: (2)