The vapour pressure of two liquids P and Q are 80 and 60 torr, respectively. The total vapour pressure of solution obtained by mixing 3 mole of P and 2 mole of Q would be
- 72 torr
- 140 torr
- 68 torr
- 20 torr
Answer
(1) 72 torr
Solution
xP = 33 + 2 = 0.6, xQ = 25 = 0.4
By Raoult's law: ptotal = pP0 xP + pQ0 xQ
= 80 0.6 + 60 0.4
= 48 + 24 = 72 torr
Answer: (1)