The correct order of energies of molecular orbitals of N2 molecule, is
- 1s < 1s < 2s < 2s < 2pz < ( 2px = 2py) < ( 2px = 2py) < 2pz
- 1s < 1s < 2s < 2s < 2pz < 2pz < ( 2px = 2py) < ( 2px = 2py)
- 1s < 1s < 2s < 2s < ( 2px = 2py) < ( 2px = 2py) < 2pz < 2pz
- 1s < 1s < 2s < 2s < ( 2px = 2py) < 2pz < ( 2px = 2py) < 2pz
Answer
(4) 1s < 1s < 2s < 2s < ( 2px = 2py) < 2pz < ( 2px = 2py) < 2pz
Solution
For B2, C2 and N2 (total electrons ≤ 14), s–p mixing raises 2pz above the 2p orbitals:
1s < 1s < 2s < 2s < ( 2px = 2py)
< 2pz < ( 2px = 2py) < 2pz
The correct order is option (4).
Answer: (4)