Equilibrium

JEE Main 2024 (Online) 29th January Evening ShiftNumericalEasy📈 Topic in 15% papers+4

Ques. 1JEE Main 2024, 29 January (Evening Shift)

The following concentrations were observed at 500 K for the formation of NH3 from N2 and H2. At equilibrium ; [N2] = 2 10-2 M, [H2] = 3 10-2 M and [NH3] = 1.5 10-2 M. Equilibrium constant for the reaction is .

Answer

417

Solution

N2(g) + 3H2(g) 2NH3(g)

Kc = [NH3]2[N2][H2]3

= (1.5 10-2)2(2 10-2)(3 10-2)3

= 2.25 10-45.4 10-7

= 416.7 ≈ 417

Answer: 417

Keep practising — Equilibrium

Ques. 2JEE Main 2024, 27 January (Morning Shift)

Given below are two statements : In the light of the above statements, choose the most appropriate answer from the options given below :

Both Statement I and Statement II are correct
Statement I is correct but Statement II is incorrect
Both Statement I and Statement II are incorrect
Statement I is incorrect but Statement II is correct

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