The standard heat of formation, in kcal/mol of Ba2+ is : [Given : standard heat of formation of SO42- ion (aq) = -216 kcal/mol, standard heat of crystallisation of BaSO4(s) = -4.5 kcal/mol, standard heat of formation of BaSO4(s) = -349 kcal/mol]
- +133.0
- +220.5
- -128.5
- -133.0
Answer
(3) -128.5
Solution
Heat of crystallisation: Ba2+(aq) + SO42-(aq) BaSO4(s); H = -4.5 kcal/mol
∵ r H = f H(products) - f H(reactants)
⇒ -4.5 = -349 - [ f H( Ba2+) + (-216)]
⇒ f H( Ba2+) = -349 + 216 + 4.5
⇒ f H( Ba2+) = -128.5 kcal/mol
Answer: (3)