An electron with kinetic energy 5 eV enters a region of uniform magnetic field of 3 perpendicular to its direction. An electric field E is applied perpendicular to the direction of velocity and magnetic field. The value of E, so that electron moves along the same path, is N C-1. (Given, mass of electron = 9 10-31 kg, electric charge = 1.6 10-19 C)
Answer
4
Solution
Undeflected: eE = evB E = vB
v = 2Km = 2 5 1.6 10-199 10-31 = 43 106 m/s
E = 43 106 3 10-6 = 4 N C-1
Answer: 4