A proton and a deuteron (q = +e, m = 2.0 u) having same kinetic energies enter a region of uniform magnetic field B, moving perpendicular to B. The ratio of the radius rd of deuteron path to the radius rp of the proton path is:
- 1 : 2
- 1 : 1
- 2 : 1
- 1 : 2
Answer
(3) 2 : 1
Solution
r = mvqB = 2mKqB
Same K, same q and same B, so r m.
rdrp = mdmp = 21 = 2, i.e. rd : rp = 2 : 1
Answer: (3)