Ques. 1JEE Main 2024, 29 January (Morning Shift)
Let A be a square matrix such that AAT=I. Then 12A [ (A+AT )2+ (A-AT )2 ] is equal to
- A2+AT
- A3+I
- A3+AT
- A2+I
Answer
(3) A3+AT
Solution
(A+AT )2+ (A-AT )2
= (A2+AAT+ATA+(AT)2 )+ (A2-AAT-ATA+(AT)2 )
=2A2+2(AT)2
∴ Expression = 12A [2A2+2(AT)2 ]=A3+(AAT)AT
=A3+IAT=A3+AT, as AAT=I
Answer: (3)