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Matrices

JEE Main 2024 (Online) 1st February Evening ShiftNumericalMedium📈 Topic in 31% papers+4
Ques. 1JEE Main 2024, 1 February (Evening Shift)

Let A=I2-2MMT, where M is a real matrix of order 2 1 such that the relation MTM=I1 holds. If is a real number such that the relation AX= X holds for some non-zero real matrix X of order 2 1, then the sum of squares of all possible values of is equal to .

Answer

2

Solution

A2=I2-4MMT+4M (MTM )MT=I2-4MMT+4MMT=I2

( MTM=I1)

AX= X A2X= AX= 2X X= 2X

X O: 2=1 = 1

(Both occur: X=M gives AM=M-2M=-M; X M gives AX=X.)

Sum of squares =1+1=2

Answer: 2

Keep practising — Matrices

Ques. 2JEE Main 2024, 29 January (Morning Shift)

Let A be a square matrix such that AAT=I. Then 12A [ (A+AT )2+ (A-AT )2 ] is equal to

  1. A2+AT
  2. A3+I
  3. A3+AT
  4. A2+I
Ques. 3JEE Main 2024, 27 January (Morning Shift)

Consider the matrix f(x)= bmatrix x & - x & 0\ x & x & 0\ 0 & 0 & 1 bmatrix. Given below are two statements : In the light of the above statements, choose the correct answer from the options given below :

  1. Statement I is false but Statement II is true
  2. Both Statement I and Statement II are false
  3. Both Statement I and Statement II are true
  4. Statement I is true but Statement II is false
Ques. 4JEE Main 2024, 27 January (Evening Shift)

Let A be a 2 2 real matrix and I be the identity matrix of order 2. If the roots of the equation |A-xI|=0 be -1 and 3, then the sum of the diagonal elements of the matrix A2 is .

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