Let P be the point in the first quadrant where the given ellipses intersect. If is the acute angle between the tangents to the given ellipses at the point P, then the value of 4 is .
Answer
7.4 to 7.6
Solution
Solving: x2=y2= 15, P ( 1 5, 1 5 ).
Slopes: x2+4y2=1 m1=- x4y=- 14; 4x2+y2=1 m2=- 4xy=-4.
= | m1-m21+m1m2 |= 15/42= 158.
4 = 152=7.5.
Answer: 7.5