2 moles each of ethylene glycol and glucose are dissolved in 500 g of water. The boiling point of the resulting solution is: (Given : Ebullioscopic constant of water = 0.52 K kg mol-1)
- 377.3 K
- 379.2 K
- 375.3 K
- 277.3 K
Answer
(1) 377.3 K
Solution
Ethylene glycol and glucose are non-electrolytes (i = 1); the elevation depends on the total moles of solute particles.
Total solute = 2 + 2 = 4 mol
m = 4 mol0.5 kg = 8 mol kg-1
Tb = Kb m = 0.52 8 = 4.16 K
Tb = 373.15 + 4.16 = 377.31 K 377.3 K
Answer: (1)