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Continuity and Differentiability

JEE Main 2025 (Online) 24th January Evening ShiftMCQMedium📈 Topic in 18% papers+4−1
Ques. 1JEE Main 2025, 24 January (Evening Shift)

Let [x] denote the greatest integer function, and let m and n respectively be the numbers of the points, where the function f(x)=[x]+|x-2|, -2<x<3, is not continuous and not differentiable. Then m+n is equal to :

  1. 6
  2. 9
  3. 8
  4. 7

Answer

(3) 8

Solution

|x-2| is continuous; only [x] jumps, at the integers -1,0,1,2 of (-2,3).

[figure]

f is discontinuous at 4 points m=4

A jump point is never differentiable; the corner of |x-2| at x=2 is already counted n=4

m+n=8

Answer: (3)

Keep practising — Continuity and Differentiability

Ques. 2JEE Main 2025, 23 January (Morning Shift)

If the function f(x)= cases 2x \ (k1+1)x+ (k2-1)x \, & x<0\\[2mm] 4, & x=0\\[2mm] 2x e ( 2+k1x2+k2x ), & x>0 cases is continuous at x=0, then k12+k22 is equal to :

  1. 5
  2. 10
  3. 20
  4. 8

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