Two cylinders, both fitted with frictionless pistons, are filled with mixtures of He and Ar gases. In the first cylinder, the masses of He and Ar are m1 and m2, respectively. In the second cylinder, the masses of He and Ar are m2 and m1, respectively. The molar mass of Ar is 10 times the molar mass of He. The external pressure applied by the piston on the first cylinder needs to be 5 times that on the second cylinder so that the volume of the gas mixtures in both the cylinders are equal at the same temperature. Assuming He and Ar behave like ideal gases, the value of (m1/m2) is .
Answer
9.80
Solution
At the same V and T, P n, so n1n2 = 5.
Let MHe = M, so MAr = 10M.
n1 = m1M+ m210M, n2 = m2M+ m110M
10m1 + m2 = 5(10m2 + m1) 5m1 = 49m2
m1m2 = 9.8
Answer: 9.80