An AC voltage V=20 200 t is applied to a series LCR circuit which drives a current I=10 (200 t+ 3 ). The average power dissipated is:
- 21.6 W
- 200 W
- 173.2 W
- 50 W
Answer
(4) 50 W
Solution
Pav=VrmsIrms = V0I02
phase difference between V and I: = 3
Pav= 20 102 60 =100 12=50 W
Answer: (4)