A transformer has an efficiency of 80\% and works at 10 V and 4 kW. If the secondary voltage is 240 V, then the current in the secondary coil is :
- 1.33 A
- 13.33 A
- 1.59 A
- 15.1 A
Answer
(2) 13.33 A
Solution
= Pout Pin Pout=0.8 4000=3200 W
Pout=VsIs
Is= 3200240=13.33 A
Answer: (2)