A poly-atomic molecule (CV=3R, CP=4R, where R is gas constant) goes from phase space point A ( PA=105 Pa, VA=4 10-6 m3 ) to point B ( PB=5 104 Pa, VB=6 10-6 m3 ) to point C ( PC=104 Pa, VC=8 10-6 m3 ). A to B is an adiabatic path and B to C is an isothermal path. The net heat absorbed per unit mole by the system is : [figure]
- 500R( 3+ 4)
- 450R( 4- 3)
- 500R 2
- 400R 4
Answer
(2) 450R( 4- 3)
Solution
A→B adiabatic ⇒ QAB=0; B→C isothermal (450 K) ⇒ U=0 ⇒ Q=W
[figure]
Q=nRT VCVB ⇒ per mole =450R 86
∴ =450R( 4- 3)
Answer: (2)