The square of the distance of the point P(5, 6, 7) from the line x-22= y-53= z-24 is equal to:
- 3
- 5
- 6
- 8
Answer
(3) 6
Solution
General point of the line: Q(2+2t, 5+3t, 2+4t)
PQ=(2t-3, 3t-1, 4t-5)
PQ line 2(2t-3)+3(3t-1)+4(4t-5)=0
29t-29=0 t=1, foot Q(4, 8, 6)
PQ2=(4-5)2+(8-6)2+(6-7)2=1+4+1=6
Answer: (3)