Let ABC be a triangle of area 15 2 and the vectors AB= i+2 j-7 k, BC=a i+b j+c k and AC=6 i+d j-2 k, d>0. Then the square of the length of the largest side of the triangle ABC is .
Answer
54
Solution
Area = 12| AB AC|=15 2 | AB AC|2=1800
AB AC= vmatrix i& j& k\\1&2&-7\\6&d&-2 vmatrix=(7d-4) i-40 j+(d-12) k
(7d-4)2+1600+(d-12)2=1800
5d2-8d-4=0 (d-2)(5d+2)=0
d=2 ( d>0)
BC= AC- AB=5 i+0 j+5 k
AB2=1+4+49=54, BC2=25+25=50, AC2=36+4+4=44
largest side is AB, AB2=54
Answer: 54