Let a=a1 i+a2 j+a3 k and b=b1 i+b2 j+b3 k be two vectors such that | a|=1, a b=2 and | b|=4. If c=2( a b)-3 b, then the angle between b and c is equal to:
- -1 (- 1 3 )
- -1 ( 23 )
- -1 ( 2 3 )
- -1 (- 32 )
Answer
(4) -1 (- 32 )
Solution
b c=2( a b) b-3| b|2=0-48=-48 ( a b b)
| a b|2=| a|2| b|2-( a b)2=16-4=12
| c|2=4| a b|2+9| b|2=48+144=192 (cross term is zero) | c|=8 3
= b c| b|| c|= -484 8 3=- 32
= -1 (- 32 )
Answer: (4)