If the rate constant for a first order reaction is k, the time (t) required for the completion of 99 % of the reaction is given by :
- t = 4.606k
- t = 2.303k
- t = 0.693k
- t = 6.909k
Answer
(1) t = 4.606k
Solution
As per NCERT, for a first order reaction
k = 2.303t [R]0[R]
For 99 % completion, [R] = [R]0 - 0.99[R]0 = 0.01[R]0
t = 2.303k [R]00.01[R]0
= 2.303k 100
= 2.303 2k
t = 4.606k
Answer: (1)