The electronic configuration of Einsteinium is : (Given atomic number of Einsteinium = 99)
- [Rn]5f136d07s2
- [Rn]5f126d07s2
- [Rn]5f116d07s2
- [Rn]5f106d07s2
Answer
(3) [Rn]5f116d07s2
Solution
Rn core has 86 electrons, so Es (Z = 99) has 99 − 86 = 13 electrons beyond [Rn].
Two go into 7s and the remaining 11 into 5f (6d stays empty, as in most later actinoids):
Es: [Rn]5f116d07s2
Answer: (3)