An engine has an efficiency of 1/6. When the temperature of sink is reduced by 62 , its efficiency is doubled. Temperatures of the source is
- 37
- 62
- 99
- 124
Answer
(3) 99
Solution
Efficiency of an ideal engine: = 1 - T2T1
Initially: 16 = 1 - T2T1 ...(i)
After lowering the sink temperature by 62 K (a change of 62 = a change of 62 K):
26 = 1 - T2 - 62T1 ...(ii)
Subtracting (i) from (ii): 16 = 62T1
T1 = 372 K
= 372 - 273 = 99
Answer: (3)