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Thermodynamics (Physics) · Question 51

AIPMT 2004MCQEasy📈 Topic in 38% papers+4−1
1

One mole of an ideal gas at an initial temperature of T K does 6R joule of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5/3, the final temperature of gas will be

  1. (T + 2.4) K
  2. (T - 2.4) K
  3. (T + 4) K
  4. (T - 4) K

Answer

(4) (T - 4) K

Solution

Work done by the gas in an adiabatic process: W = nR(T1 - T2) - 1

6R = 1 R(T - T2) 53 - 1 = 32R(T - T2)

T - T2 = 4

T2 = (T - 4) K (the gas cools as it does work)

Answer: (4)

AIPMT 2004

Keep practising — Thermodynamics (Physics)

2

An ideal gas heat engine operates in a Carnot cycle between 227 C and 127 C. It absorbs 6 kcal at the higher temperature. The amount of heat (in kcal) converted into work is equal to

  1. 4.8
  2. 3.5
  3. 1.6
  4. 1.2
AIPMT 2003
3

The efficiency of Carnot engine is 50\% and temperature of sink is 500 K. If temperature of source is kept constant and its efficiency raised to 60\%, then the required temperature of sink will be

  1. 100 K
  2. 600 K
  3. 400 K
  4. 500 K
AIPMT 2002
4

A scientist says that the efficiency of his heat engine which works at source temperature 127 and sink temperature 27 is 26\%, then

  1. it is impossible
  2. it is possible but less probable
  3. it is quite probable
  4. data are incomplete.
AIPMT 2001
5

The (W/Q) of a Carnot engine is 16, now the temperature of sink is reduced by 62 , then this ratio becomes twice, therefore the initial temperature of the sink and source are respectively

  1. 33 , 67
  2. 37 , 99
  3. 67 , 33
  4. 97 K, 37 K
AIPMT 2000

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