Let a line passing through the point (-1,2,3) intersect the lines L1: x-13= y-22= z+1-2 at M( , , ) and L2: x+2-3= y-2-2= z-14 at N(a, b, c). Then, the value of ( + + )2(a+b+c)2 equals .
Answer
196
Solution
[figure]
M(3 +1, 2 +2, -2 -1) on L1
N(-3 -2, -2 +2, 4 +1) on L2
AM=(3 +2, 2 , -2 -4)
AN=(-3 -1, -2 , 4 -2)
∵ A, M, N collinear: AM=k AN
y: 2 =-2k x: 3 +2=-3k -k=3 -k k=-2, =2
z: -4 -4=-2(4 -2) =2, =4
M(13, 10, -9) + + =14; N(-8, -2, 9) a+b+c=-1
(14)2(-1)2=196
Answer: 196