Solid State · Question 2

JEE Advanced 2024 Paper 2MCQEasy📈 Topic in 17% papers+4−1

In a metal deficient oxide sample, MXY2O4 (M and Y are metals), M is present in both +2 and +3 oxidation states and Y is in +3 oxidation state. If the fraction of M2+ ions present in M is 13, the value of X is .

0.25
0.33
0.67
0.75

Answer

(4) 0.75

Solution

Use electrical neutrality of the formula unit.

Average charge on M = 13(+2) + 23(+3) = + 83

Total positive charge = X ( 83 ) + 2(+3); total negative charge = 4 2 = 8

8X3 + 6 = 8 X = 68 = 0.75

Answer: (D)

JEE Advanced 2024 Paper 2

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