PYQSide ExamsMy practice

p-Block Elements (Group 13 & 14) · Question 32

AIPMT 2000MCQEasy📈 Topic in 50% papers+4−1
1

Which compound is electron deficient?

  1. PCl3
  2. BCl3
  3. CCl4
  4. PCl5

Answer

(2) BCl3

Solution

In BCl3, boron (3 valence electrons) forms three B–Cl bonds, so it has only 6 electrons in its valence shell (incomplete octet).

∵ As per NCERT, the trihalides of boron are electron-deficient molecules and act as Lewis acids, e.g. BCl3 + :NH3 Cl3B NH3.

In CCl4 carbon has a complete octet, and in PCl5 phosphorus has 10 electrons (expanded octet). In PCl3 phosphorus has a complete octet (three bond pairs and one lone pair).

∴ BCl3 is the electron-deficient compound.

Answer: (2)

AIPMT 2000

Keep practising — p-Block Elements (Group 13 & 14)

2

Identify the incorrect statement from the following:

  1. Oxygen exhibits only −2 oxidation state.
  2. The order of catenation property of Group 14 elements is C Si > Ge Sn.
  3. Carbon has the ability to form pπ–pπ multiple bond with itself.
  4. ECl3 (E = B and Al) is a monomer when E = B and a dimer when E = Al.
NEET (UG) 2026
3

The correct statement is

  1. Aluminium has five valence orbitals.
  2. Boron has a maximum covalency of four.
  3. Beryllium has three valence orbitals.
  4. Magnesium has a maximum covalency of four.
RE-NEET (UG) 2026
4

Match List I with List II: Choose the correct answer from the options given below:

  1. A-IV, B-I, C-II, D-III
  2. A-III, B-I, C-IV, D-II
  3. A-III, B-IV, C-I, D-II
  4. A-II, B-IV, C-I, D-III
NEET (UG) 2023
5

Taking stability as the factor, which one of the following represents correct relationship?

  1. InI3 > InI
  2. AlCl > AlCl3
  3. TlI > TlI3
  4. TlCl3 > TlCl
NEET (UG) 2023
6

Which of the following statements is not correct about diborane?

  1. There are two 3-centre-2-electron bonds.
  2. The four terminal B-H bonds are two centre two electron bonds.
  3. The four terminal hydrogen atoms and the two boron atoms lie in one plane.
  4. Both the boron atoms are sp2 hybridised.
NEET (UG) 2022
7

Choose the correct statement:

  1. Diamond and graphite have two dimensional network.
  2. Diamond is covalent and graphite is ionic.
  3. Diamond is sp3 hybridized and graphite is sp2 hybridized.
  4. Both diamond and graphite are used as dry lubricants.
Out of syllabusNEET (UG) 2022
8

Match List-I with List-II : Choose the correct answer from the options given below :

  1. (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
  2. (a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)
  3. (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
  4. (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
NEET (UG) 2022 (Phase 2)
9

Na2B4O7 heat X + NaBO2 in the above reaction the product "X" is :

  1. NaB3O5
  2. H3BO3
  3. B2O3
  4. Na2B2O5
NEET (UG) 2022 (Phase 2)
10

Identify the correct statements from the following :

  1. A and C only
  2. B and C only
  3. C and D only
  4. A, B and C only
NEET (UG) 2020
11

Which of the following is incorrect statement?

  1. GeX4 (X = F, Cl, Br, I) is more stable than GeX2
  2. SnF4 is ionic in nature
  3. PbF4 is covalent in nature
  4. SiCl4 is easily hydrolysed
NEET (UG) 2019

All p-Block Elements (Group 13 & 14) PYQs →

PDFDownload p-Block Elements (Group 13 & 14) PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All NEET Chemistry chapters