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Amines · Question 29

JEE Main 2026 (Online) 21st January Evening ShiftMCQMedium📈 Topic in 16% papers+4−1
1

[figure] Consider the above sequence of reactions. The number of bromine atom(s) in the final product (P) will be :

  1. 6
  2. 5
  3. 1
  4. 3

Answer

(2) 5

Solution

Step (1): –NO2 is a deactivating, meta-directing group m-bromonitrobenzene.

[figure]

Steps (2), (3): Sn/HCl reduces –NO2 to –NH3+ (anilinium salt); neutralisation frees the amine m-bromoaniline.

[figure]

Step (4): –NH2 is strongly activating and o/p-directing; bromine water substitutes all free o- and p-positions (2, 4, 6) 2,3,4,6-tetrabromoaniline.

[figure]

Steps (5), (6): diazotisation gives the diazonium salt ArN2 Br ; Sandmeyer reaction (CuBr) replaces – N2 by –Br pentabromobenzene.

[figure]

P (C6HBr5) contains 5 bromine atoms.

Answer: (2)

JEE Main 2026 (Online) 21st January Evening Shift

Keep practising — Amines

2

Which of the following amine(s) show(s) positive carbylamine test? Choose the correct answer from the options given below:

  1. C Only
  2. B, C and D Only
  3. A and E Only
  4. A and C Only
JEE Main 2025 (Online) 7th April Morning Shift
3

The descending order of basicity of the following amines is : Choose the correct answer from the options given below :

  1. E > A > D > C > B
  2. E > D > A > B > C
  3. E > D > B > A > C
  4. B > E > D > A > C
JEE Main 2025 (Online) 7th April Evening Shift
4

The major product (A) formed in the following reaction sequence is [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
JEE Main 2025 (Online) 4th April Morning Shift
5

Identify [A], [B] and [C], respectively in the following reaction sequence : [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
JEE Main 2025 (Online) 3rd April Morning Shift
6

In the following reactions, which one is NOT correct?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
JEE Main 2025 (Online) 3rd April Morning Shift
7

The sequence from the following that would result in giving predominantly 3,4,5-Tribromoaniline is :

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
JEE Main 2025 (Online) 3rd April Evening Shift
8

The correct order of basic nature in aqueous solution for the bases NH3, H2N-NH2, CH3CH2NH2, (CH3CH2)2NH and (CH3CH2)3N is :

  1. NH3 < H2N-NH2 < (CH3CH2)3N < CH3CH2NH2 < (CH3CH2)2NH
  2. H2N-NH2 < NH3 < (CH3CH2)3N < CH3CH2NH2 < (CH3CH2)2NH
  3. H2N-NH2 < NH3 < CH3CH2NH2 < (CH3CH2)3N < (CH3CH2)2NH
  4. NH3 < H2N-NH2 < CH3CH2NH2 < (CH3CH2)2NH < (CH3CH2)3N
JEE Main 2025 (Online) 2nd April Morning Shift
9

When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid (273 K) and acidified with acetic acid, the mass (g) of 0.1 mole of product formed is: (Given molar mass in g mol-1 H : 1, C : 12, N : 14, O : 16, S : 32)

  1. 330
  2. 33
  3. 343
  4. 66
JEE Main 2025 (Online) 2nd April Evening Shift
10

Given below are some nitrogen containing compounds : [figure] Each of them is treated with HCl separately. 1.0 g of the most basic compound will consume mg of HCl. (Given molar mass in g mol-1 C : 12, H : 1, O : 16, Cl : 35.5)

JEE Main 2025 (Online) 29th January Morning Shift
11

Consider the following sequence of reactions: [figure] 11.25 mg of chlorobenzene will produce 10-1 mg of product B. (Consider the reactions result in complete conversion.) [Given molar mass of C, H, O, N and Cl as 12, 1, 16, 14 and 35.5 g mol-1 respectively]

JEE Main 2025 (Online) 28th January Morning Shift

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