Integrals
Previous year questions with solutions · 2025 – 2026
51 Questions
31 Papers covered
6.95% ↑15.8% Weightage in 2026
Year-wise statistics questions · papers · average per paper · weightage Year Questions Papers Avg / paper Weightage 2026 33 19 1.7 6.95% ↑15.8% 2025 18 12 1.5 6.00%
All 51 MCQ 38 Numerical 13
TopicAll Definite Integral as the Limit of a Sum Evaluation of Definite Integrals by Substitution Fundamental Theorem of Calculus Integrals of the Type ∫√(ax² + bx + c) dx Integration as Inverse of Differentiation, Standard Integrals Integration by Partial Fractions Integration by Parts Integration by Substitution Properties of Definite Integrals Reduction Formulae, Leibnitz Rule and Definite Integral Inequalities (JEE) YearAll 2026 2025
31
The integral 0 8x dx4 2 x + 2 x is equal to
2 2 4 2 2 3 22
JEE Main 2025 (Online) 3rd April Evening Shift
32
Let (a, b) be the point of intersection of the curve x2 = 2y and the straight line y - 2x - 6 = 0 in the second quadrant. Then the integral I = ab 9x21 + 5x dx is equal to :
27 18 24 21
JEE Main 2025 (Online) 2nd April Evening Shift
33
4 01 ( 1 3 + x2 + 1 + x2 )dx - 3 e( 3) is equal to :
2 - 2 - e(1 + 2) 2 + 2 + e(1 + 2) 2 + 2 - e(1 + 2) 2 - 2 + e(1 + 2)
JEE Main 2025 (Online) 2nd April Evening Shift
34
The integral 80 0 4 ( + 9 + 16 2 )d is equal to :
3 4 4 3 6 43 2 3
JEE Main 2025 (Online) 29th January Morning Shift
35
If - 2 2 96x2 2 x(1 + ex) dx = ( 2 + ), , Z, then ( + )2 equals
196 100 64 144
JEE Main 2025 (Online) 28th January Morning Shift
36
Let f: R R be a twice differentiable function such that f(2) = 1. If F(x) = x f(x) for all x R, 02 x F'(x) dx = 6 and 02 x2 F''(x) dx = 40, then F'(2) + 02 F(x) dx is equal to:
13 11 9 15
JEE Main 2025 (Online) 28th January Evening Shift
37
If f(x) = 1x1/4 (1 + x1/4 )dx, f(0) = -6, then f(1) is equal to :
4 ( e 2 - 2 ) e2 2 + 2 2 - e2 4 ( e 2 + 2 )
JEE Main 2025 (Online) 28th January Evening Shift
38
Let f be a real valued continuous function defined on the positive real axis such that g(x) = 0x t f(t) dt. If g (x3 ) = x6 + x7, then value of r=115 f (r3 ) is :
270 340 310 320
JEE Main 2025 (Online) 28th January Evening Shift