The value of the integral 02 x (x2+x+1 ) ( x+1 ) ( x4+x2+1 ) dx is equal to :
- 13 e (3-2 2 )
- 23 e (4+ 2 )
- 23 e (3+2 2 )
- 13 e (1+6 2 )
Previous year questions with solutions · 2025 – 2026
| Year | Questions | Papers | Avg / paper | Weightage |
|---|---|---|---|---|
| 2026 | 33 | 19 | 1.7 | 6.95% ↑15.8% |
| 2025 | 18 | 12 | 1.5 | 6.00% |
The value of the integral 02 x (x2+x+1 ) ( x+1 ) ( x4+x2+1 ) dx is equal to :
The value of the integral - /4 /4 ( 32 4 x1+e x )dx is :
The value of the integral -11 ( x3+|x|+1x2+2|x|+1 )dx is equal to :
The value of the integral 0 e(x)x2+4 dx is:
The value of the integral 6 3 ( 4-cosec2 x 4 x )dx is :
Let (21-a+21+a ), f(a), (3a+3-a ) be in A.P. and be the minimum value of f(a). Then the value of the integral e( -1) e( ) dx (e2x-e-2x ) is :
Let f : [1, ) R be a differentiable function defined as f(x)= 1x f(t) dt +(1-x) ( e x-1 )+e. Then the value of f(f(1)) is :
Let -22 (| x|+[x x] )dx=2(3- 2)+ , where [ ] is the greatest integer function. Then ( 2 ) equals:
If =1 and =1+i 2, where i= -1 are two roots of the equation x3+ax2+bx+c=0, a, b, c R, then -11 (x3+ax2+bx+c )dx is equal to :
The integral 01 -1 (1+x+x2 )dx is equal to :
Let [.] denote the greatest integer function. Then the value of 03 ( ex+e-x[x]! )dx is :
The value of 020 ( 4 x+ 4 x )dx is equal to:
Let f(x)= ( 16x+24x2+2x-15 )dx. If f(4)=14 e(3) and f(7)= e (2 3 ), , N, then + is equal to :
Let f be a polynomial function such that f(x2 + 1) = x4 + 5x2 + 2, for all x R. Then 03 f(x) dx is equal to
If ( 1 - 5 2 x 5 x 2 x )dx = f(x) + C, where C is the constant of integration, then f ( 6 ) - f ( 4 ) is equal to
Let f(x) = dxx2/3 + 2x1/2, be such that f(0) = -26 + 24 e(2). If f(1) = a + b e(3), where a, b Z, then a + b is equal to :
Let [.] denote the greatest integer function. Then - 2 2 ( 12(3 + [x])3 + [ x] + [ x] ) dx is equal to :
Let f(t) = ( 1 - ( e t)1 - ( e t) ) dt, t > 1. If f (e /2 ) = -e /2 and f (e /4 ) = e /4, then equals
Let f(x) = (2 - x2 ) ex ( 1 + x )(1 - x)3/2 dx. If f(0) = 0, then f ( 12 ) is equal to:
The value of the integral 24 5 24 dx1 + [3] 2x is :
Let I(x) = 3 dx(4x + 6) ( 4x2 + 8x + 3 ) and I(0) = 34 + 20. If I ( 12 ) = a 2b + c, where a, b, c N, (a, b) = 1, then a + b + c is equal to :
The value of - 2 2 ( 1[x] + 4 ) dx, where [ ] denotes the greatest integer function, is
The value of - /6 /6 ( + 4x111 - (|x| + /6) )dx is equal to:
The integral -1 32 ( | 2 x ( x) | )dx is equal to:
Let f(x) be a positive function and I1 = - 121 2x f(2x(1 - 2x)) dx and I2 = -12 f(x(1 - x)) dx. Then the value of I2I1 is equal to
The integral 0 (x+3) x1+3 2 x dx is equal to
The value of -11 (1 + |x| - x ) ex + ( |x| - x ) e-xex + e-x dx is equal to
Let f(x)+2f ( 1x )=x2+5 and 2g(x)-3g ( 12 )=x, x>0. If = 12 f(x) dx, and = 12 g(x) dx, then the value of 9 + is :
Let f(x) = x3 3 - x2 dx. If 5f( 2) = -4, then f(1) is equal to
Let the domain of the function f(x) = 2 4 6 (3 + 4x - x2) be (a, b). If 0b-a [x2] dx = p - q - r, p, q, r N, (p, q, r) = 1, where [ ] is the greatest integer function, then p + q + r is equal to