If an electron in a hydrogen atom jumps from the 3rd orbit to the 2nd orbit, it emits a photon of wavelength . When it jumps from the 4th orbit to the 3rd orbit, the corresponding wavelength of the photon will be
- 1625
- 916
- 207
- 2013
Answer
(3) 207
Solution
1 = R ( 122 - 132 ) = 5R36
1 ' = R ( 132 - 142 ) = 7R144
' = 536 1447 = 207
' = 207
Answer: (3)