In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is
- 275
- 527
- 49
- 94
Answer
(2) 527
Solution
Longest wavelength of a series ⇒ transition from the next higher level
Lyman (n = 2 1): 1 L = R ( 112 - 122 ) = 3R4
Balmer (n = 3 2): 1 B = R ( 122 - 132 ) = 5R36
L B = 5R/363R/4 = 527
Answer: (2)