A block of mass m is placed on a smooth inclined wedge ABC of inclination as shown in the figure. The wedge is given an acceleration 'a' towards the right. The relation between a and for the block to remain stationary on the wedge is [figure]
- a = gcosec
- a = g
- a = g
- a = g
Answer
(4) a = g
Solution
In the frame of the wedge, a pseudo force ma acts on the block towards the left (opposite to the acceleration of the wedge).
The incline face AB slopes down towards B, so along the incline:
component of gravity down the incline = mg
component of pseudo force up the incline = ma
For the block to remain at rest on the smooth surface:
ma = mg
a = g
Answer: (4)