A plank with a box on it at one end is gradually raised about the other end. As the angle of inclination with the horizontal reaches 30 , the box starts to slip and slides 4.0 m down the plank in 4.0 s. [figure] The coefficients of static and kinetic friction between the box and the plank will be, respectively
- 0.5 and 0.6
- 0.4 and 0.3
- 0.6 and 0.6
- 0.6 and 0.5
Answer
(4) 0.6 and 0.5
Solution
The box just starts slipping at = 30 (angle of repose):
s = 30 = 1 3 0.58 0.6
Starting from rest, s = 12at2 ⇒ 4.0 = 12a(4.0)2 ⇒ a = 0.5 m s-2
Down the plank: a = g - k g
0.5 = 10 12 - k 10 32
k = 4.58.66 0.52 0.5
∴ s 0.6 and k 0.5
Answer: (4)