Two stones of masses m and 2m are whirled in horizontal circles, the heavier one in a radius r2 and the lighter one in radius r. The tangential speed of lighter stone is n times that of the value of heavier stone when they experience same centripetal forces. The value of n is
- 4
- 1
- 2
- 3
Answer
(3) 2
Solution
Let the speed of the heavier stone be v; then the lighter stone has speed nv.
Equal centripetal forces:
m(nv)2r = 2m v2r/2
n2 = 4
∴ n = 2
Answer: (3)