In some appropriate units, time (t) and position (x) relation of a moving particle is given by t = x2 + x. The acceleration of the particle is
- + 2(x+1)3
- + 22x+1
- - 2(x+2)3
- - 2(2x+1)3
Answer
(4) - 2(2x+1)3
Solution
t = x2 + x dtdx = 2x + 1
v = dxdt = 12x+1
a = dvdt = v dvdx = 12x+1 (- 2(2x+1)2 )
a = - 2(2x+1)3
Answer: (4)