A horizontal bridge is built across a river. A student standing on the bridge throws a small ball vertically upwards with a velocity 4 m s-1. The ball strikes the water surface after 4 s. The height of bridge above water surface is (Take g = 10 m s-2)
- 60 m
- 64 m
- 68 m
- 56 m
Answer
(2) 64 m
Solution
Take upward as positive and the point of projection as origin; the ball lands at displacement s = -h.
s = ut - 12gt2
-h = 4 4 - 12 10 42
-h = 16 - 80 = -64
h = 64 m
Answer: (2)