A small block slides down on a smooth inclined plane, starting from rest at time t = 0. Let Sn be the distance travelled by the block in the interval t = n - 1 to t = n. Then the ratio SnSn+1 is :
- 2n2n-1
- 2n-12n
- 2n-12n+1
- 2n+12n-1
Answer
(3) 2n-12n+1
Solution
The block moves with constant acceleration a = g from rest.
Distance in the nth second: Sn = a2(2n - 1)
Sn+1 = a2(2n + 1)
SnSn+1 = 2n-12n+1
Answer: (3)