The ratio of the distances travelled by a freely falling body in the 1st, 2nd, 3rd and 4th second
- 1 : 2 : 3 : 4
- 1 : 4 : 9 : 16
- 1 : 3 : 5 : 7
- 1 : 1 : 1 : 1
Answer
(3) 1 : 3 : 5 : 7
Solution
Distance in the nth second (starting from rest, u = 0): sn = u + g2(2n - 1) = g2(2n - 1)
s1 : s2 : s3 : s4 = 1 : 3 : 5 : 7
Answer: (3)