An unpolarized light of intensity I0 passes through polarizer and then through a certain optically active solution and finally it goes to analyser. If the angle between analyser and polariser is 0° and intensity of light emerged from analyser is 38I0, the angle of rotation of the light by the solution with respect to analyser is degrees.
Answer
30
Solution
After the polariser: I1= I02
The solution rotates the plane of polarisation by ; the analyser is parallel to the polariser, so the angle between the light's plane and the analyser is .
Malus's law: I=I1 2 = I02 2
I02 2 = 38I0 ⇒ 2 = 34 ⇒ = 32
∴ =30
Answer: 30