A gas balloon is going up with a constant velocity of 10 m/s. When this balloon reached a height of 75 m, a stone is dropped from it and balloon keeps moving up with the same velocity. The height of the balloon when the stone hits the ground is m. (Take g=10 m/s2)
- 85
- 150
- 129
- 125
Answer
(4) 125
Solution
At release the stone has the balloon's velocity: u=10 m/s upward, at height 75 m
Taking upward as positive: -75=10t- 12 10 t2
t2-2t-15=0
(t-5)(t+3)=0 t=5 s
In 5 s the balloon rises a further 10 5=50 m
height of balloon =75+50=125 m
Answer: (4)