Let z1 and z2 be two complex numbers such that z1+z2=5 and z13+z23=20+15i. Then, |z14+z24 | equals -
- 15 15
- 30 3
- 25 3
- 75
Answer
(4) 75
Solution
z13+z23=(z1+z2)3-3z1z2(z1+z2)
20+15i=125-15z1z2 z1z2=7-i
z12+z22=(z1+z2)2-2z1z2=25-2(7-i)=11+2i
z14+z24= (z12+z22 )2-2(z1z2)2
=(117+44i)-2(48-14i)=21+72i
|z14+z24 |= 212+722= 5625=75
Answer: (4)