An object moving along horizontal x-direction with kinetic energy 10 J is displaced through x = (3 i) m by the force F = (-2 i + 3 j) N. The kinetic energy of the object at the end of the displacement x is
- 10 J
- 16 J
- 4 J
- 6 J
Answer
(3) 4 J
Solution
W = F x = (-2 i + 3 j) (3 i)
= -6 J
Work–energy theorem: Kf = Ki + W
= 10 - 6 = 4 J
Answer: (3)