In the diagram shown, the normal reaction force between 2 kg and 1 kg is (Consider the surface, to be smooth) : (Given g = 10 m s-2) [figure]
- 10 N
- 25 N
- 39 N
- 6 N
Answer
(2) 25 N
Solution
Take the three blocks together (total mass = 6 kg), up the incline as positive.
Component of weight along the incline = 6 10 30 = 30 N (down the incline)
Net force = 60 - 18 - 30 = 12 N (up the incline)
a = 126 = 2 m s-2 (up the incline)
For the 1 kg block, the 2 kg block pushes it up the incline with normal force N:
N - F2 - 1 g 30 = 1 a
N - 18 - 5 = 2
N = 25 N
Answer: (2)